A baseball thrown at an angle of 65 degrees above the horizontal strikes a building 18m away at a point from?
brandon patrick asked:
which it is thrown. Ignoring air resistance what is the magnitude of the initial velocity of the baseball? The magnitude of the velocity of the baseball just before it strikes the building?And the direction of the velocity of the baseball just before it strikes the building?
which it is thrown. Ignoring air resistance what is the magnitude of the initial velocity of the baseball? The magnitude of the velocity of the baseball just before it strikes the building?And the direction of the velocity of the baseball just before it strikes the building?
15.17 m/sec … assuming it strikes the base of the building, where the building and the ground meet …
Range = v^2 [ sin (2theta) ] / g
18 = v^2 * sin ( 2*65) / 9.8
v^2 = 230.27…., so v = 15. 17 …. watch the sig figs….
The direction just as it strikes the base of the building is - 65 deg, or 65 deg BELOW the horizontal …. This is due to symmetry [ parabolic path ] of the projectile…