How many kilograms of gold are distributed throughout the oceans?
americarock҇ asked:
The element gold has properties that have made it much sought after through the ages. A cubic meter of ocean water has 6 10-6 g gold. If the total mass of the water in Earth’s oceans is 4 1020 kg (Assume that the density of seawater is 1 g/cm3.)
The element gold has properties that have made it much sought after through the ages. A cubic meter of ocean water has 6 10-6 g gold. If the total mass of the water in Earth’s oceans is 4 1020 kg (Assume that the density of seawater is 1 g/cm3.)
and then:
How many liters of seawater would have to be processed to recover 1 kg of gold (which has a value of about $8850 at 2001 prices)?
(1g / cm^3)*(100^3 cm^3 / 1 m3) = 10^6 g of water / m^3 of water, or 10^3 kg water / m^3 of water.
Now you can take the mass of ocean water, and see how many cubic meters it is in volume. 41020 kg / (10^3 kg / m^3) = ??? m^3.
Now you know how many m^3 of water is in the ocean, so multiply by the amount of gold per 1 m^3. ??? m^3*6×10^-6 = XXX grams of gold, easilly converted to kg of gold.
For this part, you need to know 1cm^3 = 1mL in terms of volume, and of course 1000mL = 1L. Then it’s just a unit conversion problem:
1 kg = 1000g = (6×10^-6 g / m^3)*??? m^3, where you have to solve for ??? then convert that to L.